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5995131806497 is a prime number
BaseRepresentation
bin101011100111101100110…
…1100111010001100100001
3210020010111001011200212011
41113033121230322030201
51241211012220301442
620430043040432521
71156063645360201
oct127173154721441
923203431150764
105995131806497
111a01580680639
12809a91618741
13346452900022
1416a24743c401
15a5e318ba117
hex573d9b3a321

5995131806497 has 2 divisors, whose sum is σ = 5995131806498. Its totient is φ = 5995131806496.

The previous prime is 5995131806401. The next prime is 5995131806509. The reversal of 5995131806497 is 7946081315995.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5895553061776 + 99578744721 = 2428076^2 + 315561^2 .

It is a cyclic number.

It is not a de Polignac number, because 5995131806497 - 231 = 5992984322849 is a prime.

It is a super-2 number, since 2×59951318064972 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5995131801497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2997565903248 + 2997565903249.

It is an arithmetic number, because the mean of its divisors is an integer number (2997565903249).

Almost surely, 25995131806497 is an apocalyptic number.

It is an amenable number.

5995131806497 is a deficient number, since it is larger than the sum of its proper divisors (1).

5995131806497 is an equidigital number, since it uses as much as digits as its factorization.

5995131806497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 73483200, while the sum is 67.

The spelling of 5995131806497 in words is "five trillion, nine hundred ninety-five billion, one hundred thirty-one million, eight hundred six thousand, four hundred ninety-seven".