6014141312671 has 2 divisors, whose sum is σ = 6014141312672. Its totient is φ = 6014141312670.

The previous prime is 6014141312629. The next prime is 6014141312687. The reversal of 6014141312671 is 1762131414106.

6014141312671 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 6014141312671 - 2¹⁵ = 6014141279903 is a prime.

It is a super-3 number, since 3×6014141312671³ (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 6014141312671.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6014141372671) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3007070656335 + 3007070656336.

It is an arithmetic number, because the mean of its divisors is an integer number (3007070656336).

Almost surely, 2^{6014141312671} is an apocalyptic number.

6014141312671 is a deficient number, since it is larger than the sum of its proper divisors (1).

6014141312671 is an equidigital number, since it uses as much as digits as its factorization.

6014141312671 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 37.

Adding to 6014141312671 its reverse (1762131414106), we get a palindrome (7776272726777).

The spelling of 6014141312671 in words is "six trillion, fourteen billion, one hundred forty-one million, three hundred twelve thousand, six hundred seventy-one".