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6015350113 is a prime number
BaseRepresentation
bin1011001101000101…
…01111010101100001
3120112012221110001221
411212202233111201
544304412200423
62432521455041
7302031426613
oct54642572541
916465843057
106015350113
112607565633
1211ba641481
1374b311886
14410c86db3
1525316ae5d
hex1668af561

6015350113 has 2 divisors, whose sum is σ = 6015350114. Its totient is φ = 6015350112.

The previous prime is 6015350101. The next prime is 6015350129. The reversal of 6015350113 is 3110535106.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4372912384 + 1642437729 = 66128^2 + 40527^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6015350113 is a prime.

It is a super-2 number, since 2×60153501132 = 72368873963938225538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (6015350153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3007675056 + 3007675057.

It is an arithmetic number, because the mean of its divisors is an integer number (3007675057).

Almost surely, 26015350113 is an apocalyptic number.

It is an amenable number.

6015350113 is a deficient number, since it is larger than the sum of its proper divisors (1).

6015350113 is an equidigital number, since it uses as much as digits as its factorization.

6015350113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1350, while the sum is 25.

The square root of 6015350113 is about 77558.6881851415. The cubic root of 6015350113 is about 1818.6688846918.

Adding to 6015350113 its reverse (3110535106), we get a palindrome (9125885219).

The spelling of 6015350113 in words is "six billion, fifteen million, three hundred fifty thousand, one hundred thirteen".