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6021132419 is a prime number
BaseRepresentation
bin1011001101110001…
…10011000010000011
3120112121211012220102
411212320303002003
544312402214134
62433245433015
7302131531631
oct54670630203
916477735812
106021132419
11260a8549a5
12120056b76b
1374c587763
14411950351
1525390e37e
hex166e33083

6021132419 has 2 divisors, whose sum is σ = 6021132420. Its totient is φ = 6021132418.

The previous prime is 6021132409. The next prime is 6021132421. The reversal of 6021132419 is 9142311206.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6021132419 is a prime.

It is a super-2 number, since 2×60211324192 = 72508071214265583122, which contains 22 as substring.

Together with 6021132421, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 6021132391 and 6021132400.

It is not a weakly prime, because it can be changed into another prime (6021132409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3010566209 + 3010566210.

It is an arithmetic number, because the mean of its divisors is an integer number (3010566210).

Almost surely, 26021132419 is an apocalyptic number.

6021132419 is a deficient number, since it is larger than the sum of its proper divisors (1).

6021132419 is an equidigital number, since it uses as much as digits as its factorization.

6021132419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The square root of 6021132419 is about 77595.9562026270. The cubic root of 6021132419 is about 1819.2514350029.

The spelling of 6021132419 in words is "six billion, twenty-one million, one hundred thirty-two thousand, four hundred nineteen".