Base | Representation |
---|---|
bin | 111000000110101010… |
… | …110100101011010101 |
3 | 12202111022212210011111 |
4 | 320012222310223111 |
5 | 1441333301300003 |
6 | 43401410535021 |
7 | 4231560500623 |
oct | 700652645325 |
9 | 182438783144 |
10 | 60241431253 |
11 | 23603798a23 |
12 | b812897471 |
13 | 58b078c613 |
14 | 2cb697c513 |
15 | 1878a42e6d |
hex | e06ab4ad5 |
60241431253 has 2 divisors, whose sum is σ = 60241431254. Its totient is φ = 60241431252.
The previous prime is 60241431233. The next prime is 60241431269. The reversal of 60241431253 is 35213414206.
60241431253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 45308102449 + 14933328804 = 212857^2 + 122202^2 .
It is a cyclic number.
It is not a de Polignac number, because 60241431253 - 229 = 59704560341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (60241431233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30120715626 + 30120715627.
It is an arithmetic number, because the mean of its divisors is an integer number (30120715627).
Almost surely, 260241431253 is an apocalyptic number.
It is an amenable number.
60241431253 is a deficient number, since it is larger than the sum of its proper divisors (1).
60241431253 is an equidigital number, since it uses as much as digits as its factorization.
60241431253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 60241431253 its reverse (35213414206), we get a palindrome (95454845459).
The spelling of 60241431253 in words is "sixty billion, two hundred forty-one million, four hundred thirty-one thousand, two hundred fifty-three".
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