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BaseRepresentation
bin100100000011101…
…100011101110111
31120011022120010012
4210003230131313
52214331321333
6140010050435
720663655536
oct4403543567
91504276105
10604948343
1129052870a
1214a719a1b
139843bccc
145a4b431d
1538198e48
hex240ec777

604948343 has 2 divisors, whose sum is σ = 604948344. Its totient is φ = 604948342.

The previous prime is 604948339. The next prime is 604948411. The reversal of 604948343 is 343849406.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 604948343 - 22 = 604948339 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 604948343.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (604941343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 302474171 + 302474172.

It is an arithmetic number, because the mean of its divisors is an integer number (302474172).

Almost surely, 2604948343 is an apocalyptic number.

604948343 is a deficient number, since it is larger than the sum of its proper divisors (1).

604948343 is an equidigital number, since it uses as much as digits as its factorization.

604948343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 248832, while the sum is 41.

The square root of 604948343 is about 24595.6976522318. The cubic root of 604948343 is about 845.7449835605.

The spelling of 604948343 in words is "six hundred four million, nine hundred forty-eight thousand, three hundred forty-three".