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60505561056011 is a prime number
BaseRepresentation
bin11011100000111100011000…
…11110010100001100001011
321221020021102120201010221012
431300132030132110030023
530412310342112243021
6332403512050234135
715513245131132301
oct1560361436241413
9257207376633835
1060505561056011
111830829a926265
126952471b8594b
13279b85ab69746
1410d26b0348271
156edd4da1635b
hex37078c79430b

60505561056011 has 2 divisors, whose sum is σ = 60505561056012. Its totient is φ = 60505561056010.

The previous prime is 60505561055993. The next prime is 60505561056013. The reversal of 60505561056011 is 11065016550506.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-60505561056011 is a prime.

Together with 60505561056013, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 60505561056011.

It is not a weakly prime, because it can be changed into another prime (60505561056013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30252780528005 + 30252780528006.

It is an arithmetic number, because the mean of its divisors is an integer number (30252780528006).

Almost surely, 260505561056011 is an apocalyptic number.

60505561056011 is a deficient number, since it is larger than the sum of its proper divisors (1).

60505561056011 is an equidigital number, since it uses as much as digits as its factorization.

60505561056011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135000, while the sum is 41.

The spelling of 60505561056011 in words is "sixty trillion, five hundred five billion, five hundred sixty-one million, fifty-six thousand, eleven".