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6066748476557 is a prime number
BaseRepresentation
bin101100001001000011001…
…1000110100110010001101
3210110222100010120111010122
41120102012120310302031
51243344200102222212
620523005322314325
71164210453126506
oct130220630646215
923428303514118
106066748476557
111a2999139a86a
1281b9399589a5
13350126c68c82
1416d8bca47bad
15a7c23dbe272
hex58486634c8d

6066748476557 has 2 divisors, whose sum is σ = 6066748476558. Its totient is φ = 6066748476556.

The previous prime is 6066748476487. The next prime is 6066748476623. The reversal of 6066748476557 is 7556748476606.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5222020210276 + 844728266281 = 2285174^2 + 919091^2 .

It is a cyclic number.

It is not a de Polignac number, because 6066748476557 - 212 = 6066748472461 is a prime.

It is a super-3 number, since 3×60667484765573 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6066748476857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3033374238278 + 3033374238279.

It is an arithmetic number, because the mean of its divisors is an integer number (3033374238279).

Almost surely, 26066748476557 is an apocalyptic number.

It is an amenable number.

6066748476557 is a deficient number, since it is larger than the sum of its proper divisors (1).

6066748476557 is an equidigital number, since it uses as much as digits as its factorization.

6066748476557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1422489600, while the sum is 71.

The spelling of 6066748476557 in words is "six trillion, sixty-six billion, seven hundred forty-eight million, four hundred seventy-six thousand, five hundred fifty-seven".