Base | Representation |
---|---|
bin | 111000110100000100… |
… | …001100100101011101 |
3 | 12211110102000101222001 |
4 | 320310010030211131 |
5 | 1444413240320001 |
6 | 44005135122301 |
7 | 4256466301411 |
oct | 706404144535 |
9 | 184412011861 |
10 | 61003057501 |
11 | 239646aa001 |
12 | b9a5973391 |
13 | 59a24c7c39 |
14 | 2d49b98d41 |
15 | 18c083a001 |
hex | e3410c95d |
61003057501 has 2 divisors, whose sum is σ = 61003057502. Its totient is φ = 61003057500.
The previous prime is 61003057487. The next prime is 61003057513. The reversal of 61003057501 is 10575030016.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 55283765625 + 5719291876 = 235125^2 + 75626^2 .
It is a cyclic number.
It is not a de Polignac number, because 61003057501 - 213 = 61003049309 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 61003057501.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61003657501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30501528750 + 30501528751.
It is an arithmetic number, because the mean of its divisors is an integer number (30501528751).
Almost surely, 261003057501 is an apocalyptic number.
It is an amenable number.
61003057501 is a deficient number, since it is larger than the sum of its proper divisors (1).
61003057501 is an equidigital number, since it uses as much as digits as its factorization.
61003057501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3150, while the sum is 28.
Adding to 61003057501 its reverse (10575030016), we get a palindrome (71578087517).
The spelling of 61003057501 in words is "sixty-one billion, three million, fifty-seven thousand, five hundred one".
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