Base | Representation |
---|---|
bin | 111000111001001011… |
… | …100110000110111101 |
3 | 12211200101111210121011 |
4 | 320321023212012331 |
5 | 2000102223230013 |
6 | 44021442435221 |
7 | 4261560640045 |
oct | 707113460675 |
9 | 184611453534 |
10 | 61088883133 |
11 | 239a909a083 |
12 | ba0a662b11 |
13 | 59b7217b35 |
14 | 2d5733a725 |
15 | 18c813ec3d |
hex | e392e61bd |
61088883133 has 2 divisors, whose sum is σ = 61088883134. Its totient is φ = 61088883132.
The previous prime is 61088883113. The next prime is 61088883157. The reversal of 61088883133 is 33138888016.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52496890884 + 8591992249 = 229122^2 + 92693^2 .
It is a cyclic number.
It is not a de Polignac number, because 61088883133 - 25 = 61088883101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61088883113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30544441566 + 30544441567.
It is an arithmetic number, because the mean of its divisors is an integer number (30544441567).
Almost surely, 261088883133 is an apocalyptic number.
It is an amenable number.
61088883133 is a deficient number, since it is larger than the sum of its proper divisors (1).
61088883133 is an equidigital number, since it uses as much as digits as its factorization.
61088883133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 663552, while the sum is 49.
The spelling of 61088883133 in words is "sixty-one billion, eighty-eight million, eight hundred eighty-three thousand, one hundred thirty-three".
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