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61114003 is a prime number
BaseRepresentation
bin1110100100100…
…0011010010011
311020222220122121
43221020122103
5111121122003
610021515111
71341313636
oct351103223
9136886577
1061114003
1131551945
1218572a97
13c87a042
14818bc1d
155572cbd
hex3a48693

61114003 has 2 divisors, whose sum is σ = 61114004. Its totient is φ = 61114002.

The previous prime is 61113971. The next prime is 61114019. The reversal of 61114003 is 30041116.

It is an a-pointer prime, because the next prime (61114019) can be obtained adding 61114003 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 61114003 - 25 = 61113971 is a prime.

It is not a weakly prime, because it can be changed into another prime (61114033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30557001 + 30557002.

It is an arithmetic number, because the mean of its divisors is an integer number (30557002).

Almost surely, 261114003 is an apocalyptic number.

61114003 is a deficient number, since it is larger than the sum of its proper divisors (1).

61114003 is an equidigital number, since it uses as much as digits as its factorization.

61114003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 61114003 is about 7817.5445633524. The cubic root of 61114003 is about 393.8947965658.

Adding to 61114003 its reverse (30041116), we get a palindrome (91155119).

The spelling of 61114003 in words is "sixty-one million, one hundred fourteen thousand, three".