Base | Representation |
---|---|
bin | 111000111010101111… |
… | …110001000010111101 |
3 | 12211202012220220110010 |
4 | 320322233301002331 |
5 | 2000130434023313 |
6 | 44024221333433 |
7 | 4262330065350 |
oct | 707257610275 |
9 | 184665826403 |
10 | 61115142333 |
11 | 23a119a4aa3 |
12 | ba17407279 |
13 | 59bc7b021b |
14 | 2d5aa14297 |
15 | 18ca5ca4c3 |
hex | e3abf10bd |
61115142333 has 8 divisors (see below), whose sum is σ = 93127835968. Its totient is φ = 34922938464.
The previous prime is 61115142313. The next prime is 61115142343. The reversal of 61115142333 is 33324151116.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 61115142333 - 225 = 61081587901 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 61115142333.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (61115142313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1455122416 + ... + 1455122457.
It is an arithmetic number, because the mean of its divisors is an integer number (11640979496).
Almost surely, 261115142333 is an apocalyptic number.
It is an amenable number.
61115142333 is a deficient number, since it is larger than the sum of its proper divisors (32012693635).
61115142333 is a wasteful number, since it uses less digits than its factorization.
61115142333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2910244883.
The product of its digits is 6480, while the sum is 30.
Adding to 61115142333 its reverse (33324151116), we get a palindrome (94439293449).
The spelling of 61115142333 in words is "sixty-one billion, one hundred fifteen million, one hundred forty-two thousand, three hundred thirty-three".
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