Base | Representation |
---|---|
bin | 101100011111001100011… |
… | …0111011111010010100001 |
3 | 210122112002022001221122112 |
4 | 1120332120313133102201 |
5 | 1300134043101120441 |
6 | 21000512212045105 |
7 | 1200513063134213 |
oct | 130763067372241 |
9 | 23575068057575 |
10 | 6114303145121 |
11 | 1a480747a9146 |
12 | 828bab903795 |
13 | 35476520a902 |
14 | 171d106b85b3 |
15 | a90a8c364eb |
hex | 58f98ddf4a1 |
6114303145121 has 2 divisors, whose sum is σ = 6114303145122. Its totient is φ = 6114303145120.
The previous prime is 6114303145073. The next prime is 6114303145127. The reversal of 6114303145121 is 1215413034116.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3586724638225 + 2527578506896 = 1893865^2 + 1589836^2 .
It is a cyclic number.
It is not a de Polignac number, because 6114303145121 - 222 = 6114298950817 is a prime.
It is a super-2 number, since 2×61143031451212 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (6114303145127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3057151572560 + 3057151572561.
It is an arithmetic number, because the mean of its divisors is an integer number (3057151572561).
Almost surely, 26114303145121 is an apocalyptic number.
It is an amenable number.
6114303145121 is a deficient number, since it is larger than the sum of its proper divisors (1).
6114303145121 is an equidigital number, since it uses as much as digits as its factorization.
6114303145121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 6114303145121 its reverse (1215413034116), we get a palindrome (7329716179237).
The spelling of 6114303145121 in words is "six trillion, one hundred fourteen billion, three hundred three million, one hundred forty-five thousand, one hundred twenty-one".
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