Base | Representation |
---|---|
bin | 1011011001000111… |
… | …11000110101000001 |
3 | 120210020220222002012 |
4 | 11230203320311001 |
5 | 100011234030213 |
6 | 2450525502305 |
7 | 304365546335 |
oct | 55443706501 |
9 | 16706828065 |
10 | 6116314433 |
11 | 2659555619 |
12 | 1228411995 |
13 | 766202288 |
14 | 4204497c5 |
15 | 25be614a8 |
hex | 16c8f8d41 |
6116314433 has 2 divisors, whose sum is σ = 6116314434. Its totient is φ = 6116314432.
The previous prime is 6116314429. The next prime is 6116314459. The reversal of 6116314433 is 3344136116.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5759595664 + 356718769 = 75892^2 + 18887^2 .
It is a cyclic number.
It is not a de Polignac number, because 6116314433 - 22 = 6116314429 is a prime.
It is a super-2 number, since 2×61163144332 = 74818604486648222978, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 6116314433.
It is not a weakly prime, because it can be changed into another prime (6116314423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3058157216 + 3058157217.
It is an arithmetic number, because the mean of its divisors is an integer number (3058157217).
Almost surely, 26116314433 is an apocalyptic number.
It is an amenable number.
6116314433 is a deficient number, since it is larger than the sum of its proper divisors (1).
6116314433 is an equidigital number, since it uses as much as digits as its factorization.
6116314433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15552, while the sum is 32.
The square root of 6116314433 is about 78206.8694744905. The cubic root of 6116314433 is about 1828.7875984089.
The spelling of 6116314433 in words is "six billion, one hundred sixteen million, three hundred fourteen thousand, four hundred thirty-three".
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