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61175046137 is a prime number
BaseRepresentation
bin111000111110010100…
…010001111111111001
312211220101122100000112
4320332110101333321
52000241302434022
644034201314105
74263655212122
oct707624217771
9184811570015
1061175046137
1123a4279a677
12ba33495935
1359cc02546a
142d64969049
1518d09ae8e2
hexe3e511ff9

61175046137 has 2 divisors, whose sum is σ = 61175046138. Its totient is φ = 61175046136.

The previous prime is 61175046083. The next prime is 61175046139. The reversal of 61175046137 is 73164057116.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55384444921 + 5790601216 = 235339^2 + 76096^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-61175046137 is a prime.

Together with 61175046139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 61175046094 and 61175046103.

It is not a weakly prime, because it can be changed into another prime (61175046139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30587523068 + 30587523069.

It is an arithmetic number, because the mean of its divisors is an integer number (30587523069).

Almost surely, 261175046137 is an apocalyptic number.

It is an amenable number.

61175046137 is a deficient number, since it is larger than the sum of its proper divisors (1).

61175046137 is an equidigital number, since it uses as much as digits as its factorization.

61175046137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 105840, while the sum is 41.

The spelling of 61175046137 in words is "sixty-one billion, one hundred seventy-five million, forty-six thousand, one hundred thirty-seven".