Base | Representation |
---|---|
bin | 101100100010110101001… |
… | …1000011111110010001101 |
3 | 210200021020121002000102002 |
4 | 1121011222120133302031 |
5 | 1300301041440001331 |
6 | 21004243204442045 |
7 | 1201210446421232 |
oct | 131055230376215 |
9 | 23607217060362 |
10 | 6122113203341 |
11 | 1a50412333513 |
12 | 82a60b3a9325 |
13 | 35540b2a8935 |
14 | 172451a5b789 |
15 | a93b47129cb |
hex | 5916a61fc8d |
6122113203341 has 2 divisors, whose sum is σ = 6122113203342. Its totient is φ = 6122113203340.
The previous prime is 6122113203319. The next prime is 6122113203347. The reversal of 6122113203341 is 1433023112216.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4787545298116 + 1334567905225 = 2188046^2 + 1155235^2 .
It is a cyclic number.
It is not a de Polignac number, because 6122113203341 - 214 = 6122113186957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6122113203347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3061056601670 + 3061056601671.
It is an arithmetic number, because the mean of its divisors is an integer number (3061056601671).
Almost surely, 26122113203341 is an apocalyptic number.
It is an amenable number.
6122113203341 is a deficient number, since it is larger than the sum of its proper divisors (1).
6122113203341 is an equidigital number, since it uses as much as digits as its factorization.
6122113203341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 6122113203341 its reverse (1433023112216), we get a palindrome (7555136315557).
The spelling of 6122113203341 in words is "six trillion, one hundred twenty-two billion, one hundred thirteen million, two hundred three thousand, three hundred forty-one".
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