Base | Representation |
---|---|
bin | 101100100011010000000… |
… | …0110010101000010101101 |
3 | 210200100120101212002002210 |
4 | 1121012200012111002231 |
5 | 1300304413142113123 |
6 | 21004512440441033 |
7 | 1201242001515135 |
oct | 131064006250255 |
9 | 23610511762083 |
10 | 6123014410413 |
11 | 1a5083500a74a |
12 | 82a821179179 |
13 | 355522c05864 |
14 | 1724d960dac5 |
15 | a94188cbe93 |
hex | 591a01950ad |
6123014410413 has 32 divisors (see below), whose sum is σ = 8225183298816. Its totient is φ = 4051514170368.
The previous prime is 6123014410361. The next prime is 6123014410417. The reversal of 6123014410413 is 3140144103216.
It is not a de Polignac number, because 6123014410413 - 213 = 6123014402221 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6123014410417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 980149656 + ... + 980155902.
It is an arithmetic number, because the mean of its divisors is an integer number (257036978088).
Almost surely, 26123014410413 is an apocalyptic number.
It is an amenable number.
6123014410413 is a deficient number, since it is larger than the sum of its proper divisors (2102168888403).
6123014410413 is a wasteful number, since it uses less digits than its factorization.
6123014410413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9333.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 6123014410413 its reverse (3140144103216), we get a palindrome (9263158513629).
The spelling of 6123014410413 in words is "six trillion, one hundred twenty-three billion, fourteen million, four hundred ten thousand, four hundred thirteen".
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