Search a number
-
+
612378282853 is a prime number
BaseRepresentation
bin10001110100101001001…
…01110000101101100101
32011112122200202222100201
420322110211300231211
540013122320022403
61145153411510501
762146206343141
oct10722445605545
92145580688321
10612378282853
11216787637727
129a8242b8431
134599329b72c
14218d4212221
1510de191221d
hex8e94970b65

612378282853 has 2 divisors, whose sum is σ = 612378282854. Its totient is φ = 612378282852.

The previous prime is 612378282809. The next prime is 612378282937. The reversal of 612378282853 is 358282873216.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 360501774724 + 251876508129 = 600418^2 + 501873^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-612378282853 is a prime.

It is a super-2 number, since 2×6123782828532 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 612378282794 and 612378282803.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (612378282653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 306189141426 + 306189141427.

It is an arithmetic number, because the mean of its divisors is an integer number (306189141427).

Almost surely, 2612378282853 is an apocalyptic number.

It is an amenable number.

612378282853 is a deficient number, since it is larger than the sum of its proper divisors (1).

612378282853 is an equidigital number, since it uses as much as digits as its factorization.

612378282853 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7741440, while the sum is 55.

The spelling of 612378282853 in words is "six hundred twelve billion, three hundred seventy-eight million, two hundred eighty-two thousand, eight hundred fifty-three".