Base | Representation |
---|---|
bin | 111001000010110000… |
… | …000010011100001011 |
3 | 12212002120121111021211 |
4 | 321002300002130023 |
5 | 2000414323300212 |
6 | 44045415513551 |
7 | 4265550401401 |
oct | 710260023413 |
9 | 185076544254 |
10 | 61249431307 |
11 | 23a80786319 |
12 | ba543888b7 |
13 | 5a1156ac5c |
14 | 2d707ad471 |
15 | 18d72a49a7 |
hex | e42c0270b |
61249431307 has 2 divisors, whose sum is σ = 61249431308. Its totient is φ = 61249431306.
The previous prime is 61249431293. The next prime is 61249431407. The reversal of 61249431307 is 70313494216.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-61249431307 is a prime.
It is a super-3 number, since 3×612494313073 (a number of 33 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 61249431307.
It is not a weakly prime, because it can be changed into another prime (61249431407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30624715653 + 30624715654.
It is an arithmetic number, because the mean of its divisors is an integer number (30624715654).
Almost surely, 261249431307 is an apocalyptic number.
61249431307 is a deficient number, since it is larger than the sum of its proper divisors (1).
61249431307 is an equidigital number, since it uses as much as digits as its factorization.
61249431307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108864, while the sum is 40.
The spelling of 61249431307 in words is "sixty-one billion, two hundred forty-nine million, four hundred thirty-one thousand, three hundred seven".
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