Base | Representation |
---|---|
bin | 111001000010110000… |
… | …000010011101101111 |
3 | 12212002120121111102112 |
4 | 321002300002131233 |
5 | 2000414323301112 |
6 | 44045415514235 |
7 | 4265550401603 |
oct | 710260023557 |
9 | 185076544375 |
10 | 61249431407 |
11 | 23a807863aa |
12 | ba5438897b |
13 | 5a1156b008 |
14 | 2d707ad503 |
15 | 18d72a4a22 |
hex | e42c0276f |
61249431407 has 2 divisors, whose sum is σ = 61249431408. Its totient is φ = 61249431406.
The previous prime is 61249431307. The next prime is 61249431409. The reversal of 61249431407 is 70413494216.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 61249431407 - 214 = 61249415023 is a prime.
Together with 61249431409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61249431409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30624715703 + 30624715704.
It is an arithmetic number, because the mean of its divisors is an integer number (30624715704).
Almost surely, 261249431407 is an apocalyptic number.
61249431407 is a deficient number, since it is larger than the sum of its proper divisors (1).
61249431407 is an equidigital number, since it uses as much as digits as its factorization.
61249431407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 41.
The spelling of 61249431407 in words is "sixty-one billion, two hundred forty-nine million, four hundred thirty-one thousand, four hundred seven".
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