Base | Representation |
---|---|
bin | 101100100101110001101… |
… | …0001001011010100111011 |
3 | 210200212120021002100110222 |
4 | 1121023203101023110323 |
5 | 1300402014142414341 |
6 | 21011210442330255 |
7 | 1201523236002554 |
oct | 131134321132473 |
9 | 23625507070428 |
10 | 6128436294971 |
11 | 1a5306757a881 |
12 | 82b894ab998b |
13 | 355ba8298b83 |
14 | 17289173132b |
15 | a96348bb44b |
hex | 592e344b53b |
6128436294971 has 2 divisors, whose sum is σ = 6128436294972. Its totient is φ = 6128436294970.
The previous prime is 6128436294823. The next prime is 6128436294973. The reversal of 6128436294971 is 1794926348216.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6128436294971 - 218 = 6128436032827 is a prime.
It is a Sophie Germain prime.
Together with 6128436294973, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (6128436294973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3064218147485 + 3064218147486.
It is an arithmetic number, because the mean of its divisors is an integer number (3064218147486).
Almost surely, 26128436294971 is an apocalyptic number.
6128436294971 is a deficient number, since it is larger than the sum of its proper divisors (1).
6128436294971 is an equidigital number, since it uses as much as digits as its factorization.
6128436294971 is an evil number, because the sum of its binary digits is even.
The product of its digits is 31352832, while the sum is 62.
The spelling of 6128436294971 in words is "six trillion, one hundred twenty-eight billion, four hundred thirty-six million, two hundred ninety-four thousand, nine hundred seventy-one".
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