Base | Representation |
---|---|
bin | 11011111000000101100001… |
… | …01111000011001110000011 |
3 | 22001001021220212010011211101 |
4 | 31330002300233003032003 |
5 | 31013322403010404413 |
6 | 334213100451555231 |
7 | 15624555304610431 |
oct | 1574026057031603 |
9 | 261037825104741 |
10 | 61300738372483 |
11 | 18594551782495 |
12 | 6a605b12bbb17 |
13 | 282883392bb0c |
14 | 111cd85da7d51 |
15 | 71488d729edd |
hex | 37c0b0bc3383 |
61300738372483 has 2 divisors, whose sum is σ = 61300738372484. Its totient is φ = 61300738372482.
The previous prime is 61300738372469. The next prime is 61300738372651. The reversal of 61300738372483 is 38427383700316.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 61300738372483 - 213 = 61300738364291 is a prime.
It is not a weakly prime, because it can be changed into another prime (61300738372403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30650369186241 + 30650369186242.
It is an arithmetic number, because the mean of its divisors is an integer number (30650369186242).
Almost surely, 261300738372483 is an apocalyptic number.
61300738372483 is a deficient number, since it is larger than the sum of its proper divisors (1).
61300738372483 is an equidigital number, since it uses as much as digits as its factorization.
61300738372483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12192768, while the sum is 55.
The spelling of 61300738372483 in words is "sixty-one trillion, three hundred billion, seven hundred thirty-eight million, three hundred seventy-two thousand, four hundred eighty-three".
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