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61302572532053 is a prime number
BaseRepresentation
bin11011111000001000111100…
…00011110100000101010101
322001001110122200102010202022
431330010132003310011111
531013340132032011203
6334214002452222525
715624651615656426
oct1574043603640525
9261043580363668
1061302572532053
1118595303048746
126a60a2360aa45
132828a6691c238
14111d0bb81364d
1571494977ea38
hex37c11e0f4155

61302572532053 has 2 divisors, whose sum is σ = 61302572532054. Its totient is φ = 61302572532052.

The previous prime is 61302572532041. The next prime is 61302572532073. The reversal of 61302572532053 is 35023527520316.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50820046077124 + 10482526454929 = 7128818^2 + 3237673^2 .

It is a cyclic number.

It is not a de Polignac number, because 61302572532053 - 24 = 61302572532037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 61302572531995 and 61302572532013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (61302572532073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30651286266026 + 30651286266027.

It is an arithmetic number, because the mean of its divisors is an integer number (30651286266027).

Almost surely, 261302572532053 is an apocalyptic number.

It is an amenable number.

61302572532053 is a deficient number, since it is larger than the sum of its proper divisors (1).

61302572532053 is an equidigital number, since it uses as much as digits as its factorization.

61302572532053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1134000, while the sum is 44.

The spelling of 61302572532053 in words is "sixty-one trillion, three hundred two billion, five hundred seventy-two million, five hundred thirty-two thousand, fifty-three".