Base | Representation |
---|---|
bin | 111001000110000001… |
… | …100110111100000111 |
3 | 12212020101222121111121 |
4 | 321012001212330013 |
5 | 2001022404301103 |
6 | 44055101214411 |
7 | 4300115352331 |
oct | 710601467407 |
9 | 185211877447 |
10 | 61304368903 |
11 | 23aa9799798 |
12 | ba6a861407 |
13 | 5a1ca648cb |
14 | 2d77bd0451 |
15 | 18dc0076bd |
hex | e46066f07 |
61304368903 has 2 divisors, whose sum is σ = 61304368904. Its totient is φ = 61304368902.
The previous prime is 61304368883. The next prime is 61304368921. The reversal of 61304368903 is 30986340316.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 61304368903 - 217 = 61304237831 is a prime.
It is a super-2 number, since 2×613043689032 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 61304368903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61304368943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30652184451 + 30652184452.
It is an arithmetic number, because the mean of its divisors is an integer number (30652184452).
Almost surely, 261304368903 is an apocalyptic number.
61304368903 is a deficient number, since it is larger than the sum of its proper divisors (1).
61304368903 is an equidigital number, since it uses as much as digits as its factorization.
61304368903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 279936, while the sum is 43.
The spelling of 61304368903 in words is "sixty-one billion, three hundred four million, three hundred sixty-eight thousand, nine hundred three".
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