Base | Representation |
---|---|
bin | 1011011010111000… |
… | …11010011001110001 |
3 | 120211021210202222121 |
4 | 11231130122121301 |
5 | 100024032211032 |
6 | 2452215234241 |
7 | 304635522313 |
oct | 55534323161 |
9 | 16737722877 |
10 | 6131132017 |
11 | 266695625a |
12 | 1231378981 |
13 | 7692bc88a |
14 | 4223c57b3 |
15 | 25d3dba97 |
hex | 16d71a671 |
6131132017 has 2 divisors, whose sum is σ = 6131132018. Its totient is φ = 6131132016.
The previous prime is 6131132003. The next prime is 6131132047. The reversal of 6131132017 is 7102311316.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6086496256 + 44635761 = 78016^2 + 6681^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6131132017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 6131131982 and 6131132000.
It is not a weakly prime, because it can be changed into another prime (6131132047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3065566008 + 3065566009.
It is an arithmetic number, because the mean of its divisors is an integer number (3065566009).
Almost surely, 26131132017 is an apocalyptic number.
It is an amenable number.
6131132017 is a deficient number, since it is larger than the sum of its proper divisors (1).
6131132017 is an equidigital number, since it uses as much as digits as its factorization.
6131132017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 756, while the sum is 25.
The square root of 6131132017 is about 78301.5454317474. The cubic root of 6131132017 is about 1830.2632343523.
The spelling of 6131132017 in words is "six billion, one hundred thirty-one million, one hundred thirty-two thousand, seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.112 sec. • engine limits •