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613310020957 is a prime number
BaseRepresentation
bin10001110110011000010…
…00000011110101011101
32011122001122000011202101
420323030020003311131
540022024331132312
61145430054125101
762211252106564
oct10731410036535
92148048004671
10613310020957
11217115577317
129aa44350791
1345ab132825a
1421981c70bdb
1510e4860ca57
hex8ecc203d5d

613310020957 has 2 divisors, whose sum is σ = 613310020958. Its totient is φ = 613310020956.

The previous prime is 613310020933. The next prime is 613310021021. The reversal of 613310020957 is 759020013316.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 472149011161 + 141161009796 = 687131^2 + 375714^2 .

It is a cyclic number.

It is not a de Polignac number, because 613310020957 - 239 = 63554207069 is a prime.

It is a super-2 number, since 2×6133100209572 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (613310020927) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 306655010478 + 306655010479.

It is an arithmetic number, because the mean of its divisors is an integer number (306655010479).

Almost surely, 2613310020957 is an apocalyptic number.

It is an amenable number.

613310020957 is a deficient number, since it is larger than the sum of its proper divisors (1).

613310020957 is an equidigital number, since it uses as much as digits as its factorization.

613310020957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34020, while the sum is 37.

The spelling of 613310020957 in words is "six hundred thirteen billion, three hundred ten million, twenty thousand, nine hundred fifty-seven".