Base | Representation |
---|---|
bin | 111001000111100111… |
… | …100101000111010001 |
3 | 12212022021021200211102 |
4 | 321013213211013101 |
5 | 2001101230200423 |
6 | 44101454154145 |
7 | 4300561515023 |
oct | 710747450721 |
9 | 185267250742 |
10 | 61331100113 |
11 | 240128972a8 |
12 | ba777b2955 |
13 | 5a25463aaa |
14 | 2d7b58c013 |
15 | 18de537c28 |
hex | e479e51d1 |
61331100113 has 2 divisors, whose sum is σ = 61331100114. Its totient is φ = 61331100112.
The previous prime is 61331100097. The next prime is 61331100143. The reversal of 61331100113 is 31100113316.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 60748939729 + 582160384 = 246473^2 + 24128^2 .
It is a cyclic number.
It is not a de Polignac number, because 61331100113 - 24 = 61331100097 is a prime.
It is a super-2 number, since 2×613311001132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (61331100143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30665550056 + 30665550057.
It is an arithmetic number, because the mean of its divisors is an integer number (30665550057).
Almost surely, 261331100113 is an apocalyptic number.
It is an amenable number.
61331100113 is a deficient number, since it is larger than the sum of its proper divisors (1).
61331100113 is an equidigital number, since it uses as much as digits as its factorization.
61331100113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 61331100113 its reverse (31100113316), we get a palindrome (92431213429).
The spelling of 61331100113 in words is "sixty-one billion, three hundred thirty-one million, one hundred thousand, one hundred thirteen".
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