Base | Representation |
---|---|
bin | 11011111000111110001001… |
… | …11001001100001001100011 |
3 | 22001011012101200200020210112 |
4 | 31330133010321030021203 |
5 | 31014322134141032031 |
6 | 334235045401121535 |
7 | 15630012566614034 |
oct | 1574370471141143 |
9 | 261135350606715 |
10 | 61331141345891 |
11 | 185a643343239a |
12 | 6a664771892ab |
13 | 282b66a636a01 |
14 | 112062bb4ca8b |
15 | 71556c90362b |
hex | 37c7c4e4c263 |
61331141345891 has 2 divisors, whose sum is σ = 61331141345892. Its totient is φ = 61331141345890.
The previous prime is 61331141345867. The next prime is 61331141345893. The reversal of 61331141345891 is 19854314113316.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 61331141345891 - 210 = 61331141344867 is a prime.
Together with 61331141345893, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (61331141345893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30665570672945 + 30665570672946.
It is an arithmetic number, because the mean of its divisors is an integer number (30665570672946).
Almost surely, 261331141345891 is an apocalyptic number.
61331141345891 is a deficient number, since it is larger than the sum of its proper divisors (1).
61331141345891 is an equidigital number, since it uses as much as digits as its factorization.
61331141345891 is an evil number, because the sum of its binary digits is even.
The product of its digits is 933120, while the sum is 50.
The spelling of 61331141345891 in words is "sixty-one trillion, three hundred thirty-one billion, one hundred forty-one million, three hundred forty-five thousand, eight hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •