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6137257353113 is a prime number
BaseRepresentation
bin101100101001111000100…
…0010110101111110011001
3210201201100000110112102002
41121103301002311332121
51301023100340244423
621015230032250345
71202254646523335
oct131236102657631
923651300415362
106137257353113
111a56883861377
128315370a09b5
13356982955ac3
1417308b0867c5
15a999deed228
hex594f10b5f99

6137257353113 has 2 divisors, whose sum is σ = 6137257353114. Its totient is φ = 6137257353112.

The previous prime is 6137257353107. The next prime is 6137257353173. The reversal of 6137257353113 is 3113537527316.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5959520911369 + 177736441744 = 2441213^2 + 421588^2 .

It is a cyclic number.

It is not a de Polignac number, because 6137257353113 - 28 = 6137257352857 is a prime.

It is not a weakly prime, because it can be changed into another prime (6137257353173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3068628676556 + 3068628676557.

It is an arithmetic number, because the mean of its divisors is an integer number (3068628676557).

Almost surely, 26137257353113 is an apocalyptic number.

It is an amenable number.

6137257353113 is a deficient number, since it is larger than the sum of its proper divisors (1).

6137257353113 is an equidigital number, since it uses as much as digits as its factorization.

6137257353113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1190700, while the sum is 47.

The spelling of 6137257353113 in words is "six trillion, one hundred thirty-seven billion, two hundred fifty-seven million, three hundred fifty-three thousand, one hundred thirteen".