Base | Representation |
---|---|
bin | 111001001010110001… |
… | …101001010111110111 |
3 | 12212102221221212202001 |
4 | 321022301221113313 |
5 | 2001203310230042 |
6 | 44111025400131 |
7 | 4302103664044 |
oct | 711261512767 |
9 | 185387855661 |
10 | 61384070647 |
11 | 2403a7868a9 |
12 | ba91499047 |
13 | 5a3341c2c3 |
14 | 2d8461a1cb |
15 | 18e3eecbb7 |
hex | e4ac695f7 |
61384070647 has 2 divisors, whose sum is σ = 61384070648. Its totient is φ = 61384070646.
The previous prime is 61384070591. The next prime is 61384070731. The reversal of 61384070647 is 74607048316.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-61384070647 is a prime.
It is a super-3 number, since 3×613840706473 (a number of 33 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 61384070597 and 61384070606.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61384076647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30692035323 + 30692035324.
It is an arithmetic number, because the mean of its divisors is an integer number (30692035324).
Almost surely, 261384070647 is an apocalyptic number.
61384070647 is a deficient number, since it is larger than the sum of its proper divisors (1).
61384070647 is an equidigital number, since it uses as much as digits as its factorization.
61384070647 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 677376, while the sum is 46.
The spelling of 61384070647 in words is "sixty-one billion, three hundred eighty-four million, seventy thousand, six hundred forty-seven".
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