Base | Representation |
---|---|
bin | 111001001010110010… |
… | …000000010010010001 |
3 | 12212102222010122110222 |
4 | 321022302000102101 |
5 | 2001203321230442 |
6 | 44111031402425 |
7 | 4302104534465 |
oct | 711262002221 |
9 | 185388118428 |
10 | 61384164497 |
11 | 2403a840367 |
12 | ba91523415 |
13 | 5a33452c36 |
14 | 2d846424a5 |
15 | 18e401a8d2 |
hex | e4ac80491 |
61384164497 has 2 divisors, whose sum is σ = 61384164498. Its totient is φ = 61384164496.
The previous prime is 61384164461. The next prime is 61384164511. The reversal of 61384164497 is 79446148316.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 55405627456 + 5978537041 = 235384^2 + 77321^2 .
It is a cyclic number.
It is not a de Polignac number, because 61384164497 - 210 = 61384163473 is a prime.
It is not a weakly prime, because it can be changed into another prime (61384161497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30692082248 + 30692082249.
It is an arithmetic number, because the mean of its divisors is an integer number (30692082249).
Almost surely, 261384164497 is an apocalyptic number.
It is an amenable number.
61384164497 is a deficient number, since it is larger than the sum of its proper divisors (1).
61384164497 is an equidigital number, since it uses as much as digits as its factorization.
61384164497 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3483648, while the sum is 53.
The spelling of 61384164497 in words is "sixty-one billion, three hundred eighty-four million, one hundred sixty-four thousand, four hundred ninety-seven".
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