Base | Representation |
---|---|
bin | 10001110111110000110… |
… | …10101111101001010001 |
3 | 2011200222102021100012102 |
4 | 20323320122233221101 |
5 | 40030040044211442 |
6 | 1150031521210145 |
7 | 62235544241102 |
oct | 10737032575121 |
9 | 2150872240172 |
10 | 614053116497 |
11 | 217466a80a67 |
12 | 9b011190955 |
13 | 45b9c276162 |
14 | 21a128263a9 |
15 | 10e8d994232 |
hex | 8ef86afa51 |
614053116497 has 2 divisors, whose sum is σ = 614053116498. Its totient is φ = 614053116496.
The previous prime is 614053116493. The next prime is 614053116557. The reversal of 614053116497 is 794611350416.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 570857313601 + 43195802896 = 755551^2 + 207836^2 .
It is a cyclic number.
It is not a de Polignac number, because 614053116497 - 22 = 614053116493 is a prime.
It is a super-2 number, since 2×6140531164972 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (614053116493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 307026558248 + 307026558249.
It is an arithmetic number, because the mean of its divisors is an integer number (307026558249).
Almost surely, 2614053116497 is an apocalyptic number.
It is an amenable number.
614053116497 is a deficient number, since it is larger than the sum of its proper divisors (1).
614053116497 is an equidigital number, since it uses as much as digits as its factorization.
614053116497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 47.
The spelling of 614053116497 in words is "six hundred fourteen billion, fifty-three million, one hundred sixteen thousand, four hundred ninety-seven".
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