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61452251640133 is a prime number
BaseRepresentation
bin11011111100011111101111…
…01000010011000101000101
322001120210000002001122122221
431332033313220103011011
531023313202404441013
6334410435155052341
715641531040255634
oct1576176750230505
9261523002048587
1061452251640133
1118642831aa2a62
126a85a368a10b1
132839bcb867503
14112643a71351b
157187aa0c508d
hex37e3f7a13145

61452251640133 has 2 divisors, whose sum is σ = 61452251640134. Its totient is φ = 61452251640132.

The previous prime is 61452251640127. The next prime is 61452251640211. The reversal of 61452251640133 is 33104615225416.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 61187954886529 + 264296753604 = 7822273^2 + 514098^2 .

It is a cyclic number.

It is not a de Polignac number, because 61452251640133 - 29 = 61452251639621 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 61452251640133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (61452251640233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30726125820066 + 30726125820067.

It is an arithmetic number, because the mean of its divisors is an integer number (30726125820067).

Almost surely, 261452251640133 is an apocalyptic number.

It is an amenable number.

61452251640133 is a deficient number, since it is larger than the sum of its proper divisors (1).

61452251640133 is an equidigital number, since it uses as much as digits as its factorization.

61452251640133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 518400, while the sum is 43.

Adding to 61452251640133 its reverse (33104615225416), we get a palindrome (94556866865549).

The spelling of 61452251640133 in words is "sixty-one trillion, four hundred fifty-two billion, two hundred fifty-one million, six hundred forty thousand, one hundred thirty-three".