Base | Representation |
---|---|
bin | 1011011101000110… |
… | …10010010011110101 |
3 | 120212120202200200112 |
4 | 11232203102103311 |
5 | 100043311223333 |
6 | 2454121352405 |
7 | 305252452601 |
oct | 55643222365 |
9 | 16776680615 |
10 | 6149711093 |
11 | 2676395a69 |
12 | 1237638705 |
13 | 7700c6306 |
14 | 424a60501 |
15 | 25ed5b948 |
hex | 16e8d24f5 |
6149711093 has 2 divisors, whose sum is σ = 6149711094. Its totient is φ = 6149711092.
The previous prime is 6149711083. The next prime is 6149711101. The reversal of 6149711093 is 3901179416.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4324114564 + 1825596529 = 65758^2 + 42727^2 .
It is a cyclic number.
It is not a de Polignac number, because 6149711093 - 214 = 6149694709 is a prime.
It is a super-3 number, since 3×61497110933 (a number of 30 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 6149711093.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6149711033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3074855546 + 3074855547.
It is an arithmetic number, because the mean of its divisors is an integer number (3074855547).
Almost surely, 26149711093 is an apocalyptic number.
It is an amenable number.
6149711093 is a deficient number, since it is larger than the sum of its proper divisors (1).
6149711093 is an equidigital number, since it uses as much as digits as its factorization.
6149711093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 41.
The square root of 6149711093 is about 78420.0936814029. The cubic root of 6149711093 is about 1832.1101096912.
The spelling of 6149711093 in words is "six billion, one hundred forty-nine million, seven hundred eleven thousand, ninety-three".
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