Base | Representation |
---|---|
bin | 11011111110110101000010… |
… | …10010010100110110110011 |
3 | 22001212102220021022002010022 |
4 | 31333122201102110312303 |
5 | 31031121332244341131 |
6 | 334511333035354055 |
7 | 15650366263164155 |
oct | 1577324122246663 |
9 | 261772807262108 |
10 | 61532407418291 |
11 | 18673824928517 |
12 | 6a994868b292b |
13 | 2844634042244 |
14 | 112a28203cad5 |
15 | 71a8ec0b537b |
hex | 37f6a1494db3 |
61532407418291 has 2 divisors, whose sum is σ = 61532407418292. Its totient is φ = 61532407418290.
The previous prime is 61532407418269. The next prime is 61532407418329. The reversal of 61532407418291 is 19281470423516.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-61532407418291 is a prime.
It is not a weakly prime, because it can be changed into another prime (61532407418221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30766203709145 + 30766203709146.
It is an arithmetic number, because the mean of its divisors is an integer number (30766203709146).
It is a 1-persistent number, because it is pandigital, but 2⋅61532407418291 = 123064814836582 is not.
Almost surely, 261532407418291 is an apocalyptic number.
61532407418291 is a deficient number, since it is larger than the sum of its proper divisors (1).
61532407418291 is an equidigital number, since it uses as much as digits as its factorization.
61532407418291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2903040, while the sum is 53.
The spelling of 61532407418291 in words is "sixty-one trillion, five hundred thirty-two billion, four hundred seven million, four hundred eighteen thousand, two hundred ninety-one".
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