Base | Representation |
---|---|
bin | 11100000000100010010001… |
… | …01000001010111110010011 |
3 | 22002002001021010202020121022 |
4 | 32000101020220022332103 |
5 | 31033101432133434044 |
6 | 334554312035150055 |
7 | 15654543423605642 |
oct | 1600211050127623 |
9 | 262061233666538 |
10 | 61591049514899 |
11 | 18696687859673 |
12 | 6aa8911a4532b |
13 | 284a01b36c8a8 |
14 | 112d04641b359 |
15 | 71c1d04db3ee |
hex | 380448a0af93 |
61591049514899 has 2 divisors, whose sum is σ = 61591049514900. Its totient is φ = 61591049514898.
The previous prime is 61591049514889. The next prime is 61591049514901. The reversal of 61591049514899 is 99841594019516.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-61591049514899 is a prime.
Together with 61591049514901, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (61591049514809) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30795524757449 + 30795524757450.
It is an arithmetic number, because the mean of its divisors is an integer number (30795524757450).
Almost surely, 261591049514899 is an apocalyptic number.
61591049514899 is a deficient number, since it is larger than the sum of its proper divisors (1).
61591049514899 is an equidigital number, since it uses as much as digits as its factorization.
61591049514899 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 125971200, while the sum is 71.
The spelling of 61591049514899 in words is "sixty-one trillion, five hundred ninety-one billion, forty-nine million, five hundred fourteen thousand, eight hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •