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61652251300141 is a prime number
BaseRepresentation
bin11100000010010100010001…
…00010011101000100101101
322002021220020101201001210001
432001022020202131010231
531040102302313101031
6335042353033544301
715662141155315465
oct1601121042350455
9262256211631701
1061652251300141
111870a633651777
126ab8752275091
132852a22a979b8
141131db0746ba5
1571dab34cd861
hex38128889d12d

61652251300141 has 2 divisors, whose sum is σ = 61652251300142. Its totient is φ = 61652251300140.

The previous prime is 61652251300121. The next prime is 61652251300151. The reversal of 61652251300141 is 14100315225616.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61030000108900 + 622251191241 = 7812170^2 + 788829^2 .

It is a cyclic number.

It is not a de Polignac number, because 61652251300141 - 241 = 59453228044589 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 61652251300141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (61652251300121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30826125650070 + 30826125650071.

It is an arithmetic number, because the mean of its divisors is an integer number (30826125650071).

Almost surely, 261652251300141 is an apocalyptic number.

It is an amenable number.

61652251300141 is a deficient number, since it is larger than the sum of its proper divisors (1).

61652251300141 is an equidigital number, since it uses as much as digits as its factorization.

61652251300141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 37.

Adding to 61652251300141 its reverse (14100315225616), we get a palindrome (75752566525757).

The spelling of 61652251300141 in words is "sixty-one trillion, six hundred fifty-two billion, two hundred fifty-one million, three hundred thousand, one hundred forty-one".