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6172561111117 is a prime number
BaseRepresentation
bin101100111010010100101…
…0011111111100001001101
3210212002110101201020222211
41121310221103333201031
51302112401121023432
621043345130310421
71204644550520452
oct131645123774115
923762411636884
106172561111117
111a6a84a913285
1283834a288411
1335a0baa91c3b
14174a79a63829
15aa868580d47
hex59d294ff84d

6172561111117 has 2 divisors, whose sum is σ = 6172561111118. Its totient is φ = 6172561111116.

The previous prime is 6172561111061. The next prime is 6172561111121. The reversal of 6172561111117 is 7111111652716.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5352994831716 + 819566279401 = 2313654^2 + 905299^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6172561111117 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 6172561111117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6172561121117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3086280555558 + 3086280555559.

It is an arithmetic number, because the mean of its divisors is an integer number (3086280555559).

Almost surely, 26172561111117 is an apocalyptic number.

It is an amenable number.

6172561111117 is a deficient number, since it is larger than the sum of its proper divisors (1).

6172561111117 is an equidigital number, since it uses as much as digits as its factorization.

6172561111117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 17640, while the sum is 40.

The spelling of 6172561111117 in words is "six trillion, one hundred seventy-two billion, five hundred sixty-one million, one hundred eleven thousand, one hundred seventeen".