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620143547502601 is a prime number
BaseRepresentation
bin1000110100000001000110101…
…1110110111101000000001001
310000022202010220002022100211101
42031000101223312331000021
51122240412441130040401
610034534002431501401
7244423615135034413
oct21500215366750011
93008663802270741
10620143547502601
1116a662446502351
1259677b83387861
13208053936116c5
14ad1d171d1d9b3
154ba6554417101
hex234046bdbd009

620143547502601 has 2 divisors, whose sum is σ = 620143547502602. Its totient is φ = 620143547502600.

The previous prime is 620143547502599. The next prime is 620143547502607. The reversal of 620143547502601 is 106205745341026.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 618980762696976 + 1162784805625 = 24879324^2 + 1078325^2 .

It is a cyclic number.

It is not a de Polignac number, because 620143547502601 - 21 = 620143547502599 is a prime.

It is a super-2 number, since 2×6201435475026012 (a number of 30 digits) contains 22 as substring.

Together with 620143547502599, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (620143547502607) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 310071773751300 + 310071773751301.

It is an arithmetic number, because the mean of its divisors is an integer number (310071773751301).

Almost surely, 2620143547502601 is an apocalyptic number.

It is an amenable number.

620143547502601 is a deficient number, since it is larger than the sum of its proper divisors (1).

620143547502601 is an equidigital number, since it uses as much as digits as its factorization.

620143547502601 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1209600, while the sum is 46.

The spelling of 620143547502601 in words is "six hundred twenty trillion, one hundred forty-three billion, five hundred forty-seven million, five hundred two thousand, six hundred one".