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620517274324141 is a prime number
BaseRepresentation
bin1000110100010110110110111…
…1101101101000110010101101
310000101001212112202020222111111
42031011231233231220302231
51122313023334211333031
610035421411150352021
7244462615342433455
oct21505555755506255
93011055482228444
10620517274324141
1116a79699755a917
12597184a37bb611
13208316b2a0c8ac
14ad332a69dad65
154bb112949a1b1
hex2345b6fb68cad

620517274324141 has 2 divisors, whose sum is σ = 620517274324142. Its totient is φ = 620517274324140.

The previous prime is 620517274324109. The next prime is 620517274324153. The reversal of 620517274324141 is 141423472715026.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 617587857229225 + 2929417094916 = 24851315^2 + 1711554^2 .

It is a cyclic number.

It is not a de Polignac number, because 620517274324141 - 25 = 620517274324109 is a prime.

It is a super-2 number, since 2×6205172743241412 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (620517274354141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 310258637162070 + 310258637162071.

It is an arithmetic number, because the mean of its divisors is an integer number (310258637162071).

Almost surely, 2620517274324141 is an apocalyptic number.

It is an amenable number.

620517274324141 is a deficient number, since it is larger than the sum of its proper divisors (1).

620517274324141 is an equidigital number, since it uses as much as digits as its factorization.

620517274324141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2257920, while the sum is 49.

The spelling of 620517274324141 in words is "six hundred twenty trillion, five hundred seventeen billion, two hundred seventy-four million, three hundred twenty-four thousand, one hundred forty-one".