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6240954798031 is a prime number
BaseRepresentation
bin101101011010001010111…
…1001001100111111001111
3211002121222212111112120011
41122310111321030333033
51304222433412014111
621135015520334051
71212615451334542
oct132642571147717
924077885445504
106240954798031
111a96857311578
12849657174327
1336369a4a3175
141780c71c0859
15ac51cb47021
hex5ad15e4cfcf

6240954798031 has 2 divisors, whose sum is σ = 6240954798032. Its totient is φ = 6240954798030.

The previous prime is 6240954797993. The next prime is 6240954798049. The reversal of 6240954798031 is 1308974590426.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6240954798031 is a prime.

It is a super-3 number, since 3×62409547980313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6240954798131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3120477399015 + 3120477399016.

It is an arithmetic number, because the mean of its divisors is an integer number (3120477399016).

It is a 1-persistent number, because it is pandigital, but 2⋅6240954798031 = 12481909596062 is not.

Almost surely, 26240954798031 is an apocalyptic number.

6240954798031 is a deficient number, since it is larger than the sum of its proper divisors (1).

6240954798031 is an equidigital number, since it uses as much as digits as its factorization.

6240954798031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13063680, while the sum is 58.

The spelling of 6240954798031 in words is "six trillion, two hundred forty billion, nine hundred fifty-four million, seven hundred ninety-eight thousand, thirty-one".