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625125750113 is a prime number
BaseRepresentation
bin10010001100011000110…
…01011111010101100001
32012202120002101102000202
421012030121133111201
540220224143000423
61155102342154545
763110125126544
oct11061431372541
92182502342022
10625125750113
11221129209537
12a11a1422a55
1346c45251c77
142238320285b
15113daace728
hex918c65f561

625125750113 has 2 divisors, whose sum is σ = 625125750114. Its totient is φ = 625125750112.

The previous prime is 625125750103. The next prime is 625125750131. The reversal of 625125750113 is 311057521526.

Together with next prime (625125750131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 411481195024 + 213644555089 = 641468^2 + 462217^2 .

It is a cyclic number.

It is not a de Polignac number, because 625125750113 - 210 = 625125749089 is a prime.

It is not a weakly prime, because it can be changed into another prime (625125750103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 312562875056 + 312562875057.

It is an arithmetic number, because the mean of its divisors is an integer number (312562875057).

Almost surely, 2625125750113 is an apocalyptic number.

It is an amenable number.

625125750113 is a deficient number, since it is larger than the sum of its proper divisors (1).

625125750113 is an equidigital number, since it uses as much as digits as its factorization.

625125750113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63000, while the sum is 38.

The spelling of 625125750113 in words is "six hundred twenty-five billion, one hundred twenty-five million, seven hundred fifty thousand, one hundred thirteen".