Base | Representation |
---|---|
bin | 1000111101000110111110011… |
… | …1110000010001001000110011 |
3 | 10001122010210112002120001010201 |
4 | 2033101233213300101020303 |
5 | 1130043203222321211033 |
6 | 10112110154311340031 |
7 | 246505054001004436 |
oct | 21721574760211063 |
9 | 3048123462501121 |
10 | 630140015022643 |
11 | 172866974844944 |
12 | 5a811434081617 |
13 | 2107bc4396a8a8 |
14 | b186d21c3781d |
15 | 4ccb5c418447d |
hex | 23d1be7c11233 |
630140015022643 has 2 divisors, whose sum is σ = 630140015022644. Its totient is φ = 630140015022642.
The previous prime is 630140015022611. The next prime is 630140015022671. The reversal of 630140015022643 is 346220510041036.
630140015022643 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 630140015022643 - 25 = 630140015022611 is a prime.
It is not a weakly prime, because it can be changed into another prime (630140015023643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 315070007511321 + 315070007511322.
It is an arithmetic number, because the mean of its divisors is an integer number (315070007511322).
Almost surely, 2630140015022643 is an apocalyptic number.
630140015022643 is a deficient number, since it is larger than the sum of its proper divisors (1).
630140015022643 is an equidigital number, since it uses as much as digits as its factorization.
630140015022643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 630140015022643 its reverse (346220510041036), we get a palindrome (976360525063679).
The spelling of 630140015022643 in words is "six hundred thirty trillion, one hundred forty billion, fifteen million, twenty-two thousand, six hundred forty-three".
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