Base | Representation |
---|---|
bin | 1000111101000110111110011… |
… | …1110000010001001000010011 |
3 | 10001122010210112002120001002112 |
4 | 2033101233213300101020103 |
5 | 1130043203222321210421 |
6 | 10112110154311335535 |
7 | 246505054001004362 |
oct | 21721574760211023 |
9 | 3048123462501075 |
10 | 630140015022611 |
11 | 172866974844915 |
12 | 5a8114340815ab |
13 | 2107bc4396a882 |
14 | b186d21c377d9 |
15 | 4ccb5c418445b |
hex | 23d1be7c11213 |
630140015022611 has 2 divisors, whose sum is σ = 630140015022612. Its totient is φ = 630140015022610.
The previous prime is 630140015022541. The next prime is 630140015022643. The reversal of 630140015022611 is 116220510041036.
It is an a-pointer prime, because the next prime (630140015022643) can be obtained adding 630140015022611 to its sum of digits (32).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 630140015022611 - 230 = 630138941280787 is a prime.
It is not a weakly prime, because it can be changed into another prime (630140015022671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 315070007511305 + 315070007511306.
It is an arithmetic number, because the mean of its divisors is an integer number (315070007511306).
Almost surely, 2630140015022611 is an apocalyptic number.
630140015022611 is a deficient number, since it is larger than the sum of its proper divisors (1).
630140015022611 is an equidigital number, since it uses as much as digits as its factorization.
630140015022611 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 630140015022611 its reverse (116220510041036), we get a palindrome (746360525063647).
The spelling of 630140015022611 in words is "six hundred thirty trillion, one hundred forty billion, fifteen million, twenty-two thousand, six hundred eleven".
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