Base | Representation |
---|---|
bin | 10010010101111110000… |
… | …01100000100011110111 |
3 | 2020020211121022212212021 |
4 | 21022333001200203313 |
5 | 40311243114201413 |
6 | 1201313030534011 |
7 | 63351452123002 |
oct | 11127701404367 |
9 | 2206747285767 |
10 | 630270068983 |
11 | 223329028435 |
12 | a2198207307 |
13 | 47584c70929 |
14 | 22710510539 |
15 | 115dc54218d |
hex | 92bf0608f7 |
630270068983 has 2 divisors, whose sum is σ = 630270068984. Its totient is φ = 630270068982.
The previous prime is 630270068927. The next prime is 630270069113. The reversal of 630270068983 is 389860072036.
630270068983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 630270068983 - 217 = 630269937911 is a prime.
It is a super-3 number, since 3×6302700689833 (a number of 36 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 630270068983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (630270068083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 315135034491 + 315135034492.
It is an arithmetic number, because the mean of its divisors is an integer number (315135034492).
Almost surely, 2630270068983 is an apocalyptic number.
630270068983 is a deficient number, since it is larger than the sum of its proper divisors (1).
630270068983 is an equidigital number, since it uses as much as digits as its factorization.
630270068983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2612736, while the sum is 52.
The spelling of 630270068983 in words is "six hundred thirty billion, two hundred seventy million, sixty-eight thousand, nine hundred eighty-three".
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