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63130019 is a prime number
BaseRepresentation
bin1111000011010…
…0100110100011
311101210100002212
43300310212203
5112130130034
610133032335
71364411351
oct360644643
9141710085
1063130019
11326a9577
12191856ab
1310104854
1485547d1
1558202ce
hex3c349a3

63130019 has 2 divisors, whose sum is σ = 63130020. Its totient is φ = 63130018.

The previous prime is 63130007. The next prime is 63130031. The reversal of 63130019 is 91003136.

63130019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (63130007) and next prime (63130031).

It is a cyclic number.

It is not a de Polignac number, because 63130019 - 24 = 63130003 is a prime.

It is a super-2 number, since 2×631300192 = 7970798597880722, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 63129976 and 63130003.

It is not a weakly prime, because it can be changed into another prime (63130099) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31565009 + 31565010.

It is an arithmetic number, because the mean of its divisors is an integer number (31565010).

Almost surely, 263130019 is an apocalyptic number.

63130019 is a deficient number, since it is larger than the sum of its proper divisors (1).

63130019 is an equidigital number, since it uses as much as digits as its factorization.

63130019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 23.

The square root of 63130019 is about 7945.4401388469. The cubic root of 63130019 is about 398.1792644633.

The spelling of 63130019 in words is "sixty-three million, one hundred thirty thousand, nineteen".