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631454973113 is a prime number
BaseRepresentation
bin10010011000001011010…
…01100011110010111001
32020100220011221020202102
421030011221203302321
540321204433114423
61202030355313145
763423020465666
oct11140551436271
92210804836672
10631454973113
11223886963448
12a2468bab7b5
13477135aac33
14227c3a30a6d
151165b599c28
hex9305a63cb9

631454973113 has 2 divisors, whose sum is σ = 631454973114. Its totient is φ = 631454973112.

The previous prime is 631454973031. The next prime is 631454973139. The reversal of 631454973113 is 311379454136.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 347661178384 + 283793794729 = 589628^2 + 532723^2 .

It is a cyclic number.

It is not a de Polignac number, because 631454973113 - 212 = 631454969017 is a prime.

It is not a weakly prime, because it can be changed into another prime (631454973613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 315727486556 + 315727486557.

It is an arithmetic number, because the mean of its divisors is an integer number (315727486557).

Almost surely, 2631454973113 is an apocalyptic number.

It is an amenable number.

631454973113 is a deficient number, since it is larger than the sum of its proper divisors (1).

631454973113 is an equidigital number, since it uses as much as digits as its factorization.

631454973113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 816480, while the sum is 47.

The spelling of 631454973113 in words is "six hundred thirty-one billion, four hundred fifty-four million, nine hundred seventy-three thousand, one hundred thirteen".