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632015117 is a prime number
BaseRepresentation
bin100101101010111…
…100100100001101
31122001020200202022
4211222330210031
52243243440432
6142414135525
721443016446
oct4552744415
91561220668
10632015117
112a4835348
121577b15a5
13a0c27b56
145dd1c2cd
153a743b12
hex25abc90d

632015117 has 2 divisors, whose sum is σ = 632015118. Its totient is φ = 632015116.

The previous prime is 632015057. The next prime is 632015129. The reversal of 632015117 is 711510236.

632015117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 631969321 + 45796 = 25139^2 + 214^2 .

It is a cyclic number.

It is not a de Polignac number, because 632015117 - 26 = 632015053 is a prime.

It is a super-3 number, since 3×6320151173 (a number of 27 digits) contains 333 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (632015147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 316007558 + 316007559.

It is an arithmetic number, because the mean of its divisors is an integer number (316007559).

Almost surely, 2632015117 is an apocalyptic number.

It is an amenable number.

632015117 is a deficient number, since it is larger than the sum of its proper divisors (1).

632015117 is an equidigital number, since it uses as much as digits as its factorization.

632015117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260, while the sum is 26.

The square root of 632015117 is about 25139.9108391418. The cubic root of 632015117 is about 858.1749276117.

The spelling of 632015117 in words is "six hundred thirty-two million, fifteen thousand, one hundred seventeen".