Base | Representation |
---|---|
bin | 11100101111011110101010… |
… | …10110010001101010001101 |
3 | 22021210020122001012112021201 |
4 | 32113233111112101222031 |
5 | 31241013314411202044 |
6 | 342231305530025501 |
7 | 16212224420350513 |
oct | 1627572526215215 |
9 | 267706561175251 |
10 | 63204023147149 |
11 | 19158748382a85 |
12 | 7109443578291 |
13 | 29361630649b1 |
14 | 118713bb6c4b3 |
15 | 749135a647d4 |
hex | 397bd5591a8d |
63204023147149 has 2 divisors, whose sum is σ = 63204023147150. Its totient is φ = 63204023147148.
The previous prime is 63204023147143. The next prime is 63204023147171. The reversal of 63204023147149 is 94174132040236.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 48020492621124 + 15183530526025 = 6929682^2 + 3896605^2 .
It is a cyclic number.
It is not a de Polignac number, because 63204023147149 - 225 = 63203989592717 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 63204023147099 and 63204023147108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (63204023147143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31602011573574 + 31602011573575.
It is an arithmetic number, because the mean of its divisors is an integer number (31602011573575).
Almost surely, 263204023147149 is an apocalyptic number.
It is an amenable number.
63204023147149 is a deficient number, since it is larger than the sum of its proper divisors (1).
63204023147149 is an equidigital number, since it uses as much as digits as its factorization.
63204023147149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 46.
The spelling of 63204023147149 in words is "sixty-three trillion, two hundred four billion, twenty-three million, one hundred forty-seven thousand, one hundred forty-nine".
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