Base | Representation |
---|---|
bin | 111010111001100010… |
… | …101000010111011011 |
3 | 20001020110202001200212 |
4 | 322321202220113123 |
5 | 2014010023432324 |
6 | 45015252121335 |
7 | 4366130401331 |
oct | 727142502733 |
9 | 201213661625 |
10 | 63242405339 |
11 | 249037641a3 |
12 | 1030b90624b |
13 | 5c6b425329 |
14 | 30bd359b51 |
15 | 19a222a70e |
hex | eb98a85db |
63242405339 has 2 divisors, whose sum is σ = 63242405340. Its totient is φ = 63242405338.
The previous prime is 63242405327. The next prime is 63242405341. The reversal of 63242405339 is 93350424236.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 63242405339 - 216 = 63242339803 is a prime.
It is a super-3 number, since 3×632424053393 (a number of 33 digits) contains 333 as substring.
Together with 63242405341, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 63242405296 and 63242405305.
It is not a weakly prime, because it can be changed into another prime (63242405309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31621202669 + 31621202670.
It is an arithmetic number, because the mean of its divisors is an integer number (31621202670).
Almost surely, 263242405339 is an apocalyptic number.
63242405339 is a deficient number, since it is larger than the sum of its proper divisors (1).
63242405339 is an equidigital number, since it uses as much as digits as its factorization.
63242405339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 41.
The spelling of 63242405339 in words is "sixty-three billion, two hundred forty-two million, four hundred five thousand, three hundred thirty-nine".
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